Question

Reeta is twice as old as gella six years ago her age was three times gella find their present ages​

Answer 1

Step-by-step explanation:

Let Arjun be designated as A

Let Shriya be designated as S.

A is twice as old as S

Let S be x years old currently.

Therefore A is 2(x) years old currently.

5 years ago S was ( x - 5 ) years old

5 years ago A was (2(x) - 5) years old

5 years ago A was three times S' age.

That is, 5 years ago, ( 2x - 5 ) = 3( x - 5 )

or

2x - 5 = 3x - 15 so

3x - 2x = -5 + 15 or

x = 10

I stated that S' Current age was x years old. We have now identified x as 10 years old.

A is therefore identified as 2x years old or 20 years old.

Therefore currently Arjun and Shryia are 20 and 10 years old respectively.

Note that 5 years ago A was 15 and S was 5, so A was three times S' age.

Answer 2

Answer:

30 and 15

Step-by-step explanation:

At present:

Age of Gella = x

Age of Reeta = 2x

6 years ago:

Age of Gella = x - 6

Ageof Reeta = 2x - 3

Given,

2x - 3 = 3(x - 6)

2x - 3 = 3x - 18

18 - 3 = 3x - 2x

15 = x

Present age of Reeta = 30

Present age of Reeta = 30Present age of Gella = 15

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