Reeta was studying in the class 9th of St. Surya Public School. Mehrauli, New
Delhi-110030 Once Ranjeet and his daughter Reeta were returning after attending
teachers parent meeting at Reeta's school. As the home of Ranjeet was close to the
school so they were coming by waking.
Reeta asked her father. "Daddy how old are you?"
Ranjeet said. "Sum of ages of both of us is 55 years. After 10 years my age will be
double of you. Now you find ages of both of us"
If Ranjeet's present age is x years and Reeta's present age is y vears, then
i. What is the first equation formed?
X - V=55
b.x+v=55
x + 2y =53
d 2x + y =55
ii. What is the second equation formed?
X-V=10
b x+y=10
x + 2y = 20
dx - 2y = 10
a.
C.
10 po
Option 1
Answers
Step-by-step explanation:
i. What is the first equation formed?
b. x + y =55
ii. What is the second equation formed?
iii. If (4, 2) is the solution of 2x+ky=10, then k=
x=4, y=2
2x+Ky=10
2×4+2k=10
8+2k=10
2k=10-8
2k=2
k=2
2
k=1
iv. If Father’s present age is 45 years, then Reeta’s present age is
Father’s present age ,x=45
x+y=55
45+y=55
y=55-45
y=10 years
v. If the ratio of age of Reeta and her mother is 3:7 and sum of ages is 50 years,
then Reeta's mother’s age is
Reeta =3x
Reeta's mother’s=7x
3x+7x=50
10x=50
x =50
10
x=5
Reeta =3x
3×5
15 years
Reeta's mother’s=7x
= 7×5
=35 years
Given :
Sum of ages of Daughter and father is 55 years
After 10 years my age of father will be Double of Daughter's age.
To Find : What is the first equation formed
What is the second equation formed
Solution:
Let say Reeta's present age = y Years
Ranjeet's present age = x Years
Sum of ages of both is 55 years
=> x + y = 55
After 10 years Reeta's age = y + 10 Years
After 10 years Ranjeet's age = x+ 10 Years
x + 10 = 2(y + 10)
=> x + 10 = 2y + 20
=> x - 2y = 10
y = 15
x = 40
Daughter Reeta's age = 15 Years
Father Ranjeet's Age = 40 Years
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