Question

Ref. &
27. Find the area and periphery of a quadrant of circle whose diameter is 14 cm.
(Apprentice October 2006, Sheet Metal W
Welder, Forger & Heat Tre​

Answer 1

Answer:

AREA OF QUADRANT= 1/4* πr²

= 1/4 * 22/7 * 7*7

= 38.5 cm²

Perimeter= 1/4 * 2πr

= 1/4 * 2 * 22/7 *7

= 11 cm

Answer 2

Diameter of quadrant = 14 cm

$\text{Perimeter = } \bf \bigg\{\frac{1}{4} \times (2 \pi r) \bigg\} + 2r\\ \rm |or| \\ \bf \bigg\{\frac{1}{4} \times ( \pi d) \bigg\} + d \\ \\ = > \bigg( \frac{1}{4} \times \frac{22}{7} \times 14 \bigg) + 14\\ \\ = > 14\bigg( \frac{22}{28} + 1\bigg) \\ \\ = > 14\bigg( \frac{22 + 28}{28} \bigg) \\ \\ = > 14\bigg( \frac{50}{28} \bigg) \\ \\ = > \frac{50}{2} \: \: \: \: \rm = 25 \: cm$

Area = πr²/4

$\tt = > \frac{ \frac{22}{7} \times {(7)}^{2} }{4} \\ \\ \tt = > \frac{ 22 \times 7 }{4} = \frac{154}{4} \\ \\ \sf = > 38.5 \: \: {cm}^{2}$