Question

Refer above figure
Given,
O is center of the circle and QR = QP. find value of x ​

Answer 1

Answer:

X=60°

Step-by-step explanation:

In the figure given above 'O' is the centre of the circle

If QR=OP and angle ORP = 20°

Therefore, QR=OP

Therefore, QR=OP=OQ

Hence,

Triangle OQR is isosceles triangle

Angle QRO = 180° - 20° - 20°

= 140°

THEREFORE,

ANGLE OQP = 40° (LINEAR PAIR OF ANGLE OQR)

ANGLE OPQ = 40° (TRIANGLE OPQ IS ISOSCELES)

ANGLE POQ = 180° - 40° - 40°

= 100°

THEREFORE,

ANGLE POT = X

= 180° - 100° - 20°

= 60°