Question

refer attached in picture

Answer 1

∆ABC & ∆ ADB
side AB = SIDE AD ...... GIVEN
SIDE BC = SIDE DC ..... GIVEN
SIDE AC = SIDE AC.... COMMON SIDES

THEREFORE
∆ABC = ∆ ADC .... S.S.S TEST.
THERFORE
ANGLE B = ANGLE D .....C.A.C.T.

Answer 2

Given : AB = AD nd BC = CD

To prove : ∆ABC ~ ∆ADC

Proof: In ∆ABC nd ∆ADC
AB = AD {given}
BC =CD                    {given}
AC=AC                {common}
                 ∆ABC~∆ADC  { by SSS}
angleB=angleD { by,CPCT}

hope it helps u!
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