Math, asked by Anonymous, 9 months ago

Refer the attachment and please answer with step-by-step explaination only....
Answer both questions please...
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Answers

Answered by DrNykterstein
1

1)

3x - 9y = 12 { divide by 3 }

x - 3y = 4 ...(1)

On comparing,

a1 = 1 , b1 = -3, c1 = 4

(i) Intersecting:

px + qy = dc ...(2)

on comparing,

a2 = p , b2 = q , c2 = d

For intersecting lines:

a1/a2 ≠ b1/b2

1/p ≠ -3/q

p ≠ 1 , and q ≠ -3

So,

Required linear equation = 2x + y = 1

(ii) coincident

Multiply the equation (1) by 2

Required linear equation:

==> 2x - 6y = 8

(iii) Parallel

ex + fy = gc ...(3)

On comparing,

a3 = e , b3 = f , c3 = g

For Parallel line:

a1/a3 = b1/b3 ≠ c1/c3

a1/a3 = b1/b3 ; b1/b3 ≠ c1/c3

1/e = -3/f ; -3/f ≠ 4/g

e = 1 and f = -3 ; f ≠ -3 and g ≠ 4

Required linear equation:

==> x - 3y = 3

2)

ax + 3y = a - 3 ; 12x + ay = 0

On comparing,

a1 = a , b1 = 3 , c1 = a-3 ; a2 = 12 , b2 = a , c2 = 0

For no solutions, lines must be parallel to each other:

a1/a2 = b1/b2 ≠ c1/c2

a1/a2 = b1/b2 ; b1/b2 ≠ c1/c2

a/12 = 3/a ; b1 c2 ≠ c1 b2

a² = 36 ; 0 ≠ a² - 3a

a = -6, 6 ; a ≠ 3

Hence, value of a are 6 and -6

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