Physics, asked by princess2748, 1 month ago

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Answers

Answered by rajv63020vishalraj
0

Answer:

Given,

Magnification, m=3

Object distance, u=10cm

We know,

Magnification, m=−

u

v

3=

−10

−v

⇒ v=30cm

From mirror formula,

f

1

=

v

1

+

u

1

f

1

=

30

1

10

1

=

30×10

10−30

=

300

−20

f=−15cm

Focal length, f=−15cm

Answered by Anonymous
24

Answer:

Given that

u= -10 cm

f= 15 cm

Find out

We need to find v

Formula

We know the formula

1/f = 1/v + 1/u

Therefore, 1/v= 1/f – 1/u

Substituting the known values in the above equation we get,

1/v= 1/15 + 1/10

1/v = (2+3)/30 (lcm)

Hencev=5/30 = 6 cm

v= 6cm

Nature of the image: The image is formed behind the mirror and it is virtual and erect.

KUCH NOI HUA..

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Btw Mai pc use kr raha hun so i can't talk in b.i.o

Explanation:

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