Question

refer to attachment​

Answer 1

Let ∠ a = 2x, then ∠b = 3x

(sum of angle in linear pair always equal to 180° )

∠XOM + ∠MOP + ∠POY = 180°

∠b + ∠a + ∠POY = 180°

given that ∠POY = 90°

plug this value we get

3x + 2x + 90° = 180°

5x = 90°

x = 18°

a = 2x = 2 × 18 = 36°

b = 3x = 3 ×18 = 54°

MN is a straight line.

sum of angle in linear pair always equal to 180°

so that ∠b + ∠c = 180°

54° + ∠c = 180°

∠c = 180° − 54° = 126°

∠ c = 126°

Answer 2

Explanation:

Let 2 a = 2x, then 2b = 3x

(sum of angle in linear pair always

equal to 180°)

ZXOM + ZMOP + ZPOY = 180°

<b+ 2a + ZPOY = 180°

given that ZPOY = 90°

plug this value we get

3x + 2x + 90° = 180°

5x = 90°

= 18°

= 2x

= 2 x 18

= 36°

= 3x

= 3 x18

= 54°

MN is a straight line.

sum of angle in linear pair always equal

to 180°

so that

Zb+ 2C

= 180°

54° + 20 = 180°

20 = 180° - 54° = 126°

cc = 126°