Question

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REFER TO THE ABOVE ATTACHMENT ND SOLVE IT.
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Answer 1

molecular mass of Na2So4.10H2O =

46 + 32 +64 + 180 =322g

given mass = 664g

Mole = 664/332= 2mole

total number of gram molecule present = 2*6.022*10^-23= 12 .044*10^23