Question

refer to the attachment ☹️☹️☹️☹️☹️☹️☹️☹️☹️☹️​

Answer 1

Answer:

$\Large{\boxed{\underline{\overline{\mathfrak{\star \: QuEsTiOn :- \: \star}}}}}$

Find the zeros of the quadratic polynomials of the given equation and verify the relationship between the coefficients and zeros. Use

alpha and beta

4u² + 8u

$\huge\underline{\overline{\mid{\bold{\pink{ANSWER-}}\mid}}}$

GIVEN:

Quadratic polynomial = 4u² + 8u

TO FIND:

Zeroes and verify the relationship between the coefficients and zeros.

$\Large{\underline{\underline{\bf{SoLuTion:-}}}}$

4u² + 8u = 0

4u(u + 2) = 0

4u = 0 ; u + 2 = 0

u = 0 ; u = -2

The zeroes of polynomial are 0 and -2

VERIFICATION:

Sum of zeroes = 0 + (-2) = -2

Product of zeroes = 0 × -2 = 0

Using coefficients,

Sum of zeroes = -b/a = -8/4 = -2

Product of zeroes = c/a = 0/4 = 0

$\mathfrak{\huge{\purple{\underline{\underline{Hence}}}}}$

$\huge\green{\mid{\fbox{\tt{VERIFIED}}\mid}}$

Answer 2

Answer:

a−b = 4−(8)=−2

Mark as brainliest please for the effort

Step-by-step explanation:

Let f(u)=4u

2 +8u

To calculate the zeros of the given equation, put f(u)=0.

4u 2 +8u=0

4u(u+2)=0

u=0,u=−2

The zeros of the given equation is 0 and −2.

Sum of the zeros is 0+(−2)=−2.

Product of the zeros is 0×−2=0.

According to the given equation,

The sum of the zeros is,