Question

Refer to the attachment....

Answer 1

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YOUR SOLUTION IS IN THE ATTACHMENT.


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Answer 2

tanA / (1-1/tanA)+(1/tanA)/(1-tanA) =tan2A / (tanA-1)+1 / (tanA(1-tanA))= (1 / (1-tanA)) ((1 / tanA)-tan2A)= (1 / (1-tanA)) ((1-tan3A) / tanA)1-tan3A= (1-tanA) (1+tanA+tan2A)=1 / tanA+1+tanA=1+tanA+cotA.I hope this answer I hope this answer is helpful to you