Math, asked by nikita0770, 7 days ago

refer to the attachment...​

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Answered by qwerty1123
1

Answer:

one of the zero is 6

sum of zeroes is=0

so let the other zero be b

so 6+b=0

b=0-6=-6

product of the zeroes=6*-6=-36

so the polynomial is x²-(-6+6)x+(6*-6)=0

x²-0x-36=0

thus x²-36 is the required polynomial.

hope it helps

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