Math, asked by prachikapoor63, 5 months ago

refer to the attachment and answer correctly​

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Answered by Intelligentcat
32

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Given Expression,

 \displaystyle \sf \: l =  \int \:  {x}^{2}  \sqrt{1 + x}  \: dx

Assuming x + 1 = t

Differentiating both sides of the equation,

 \sf \: \: dx = dt

The expression would be re written as :

 \longrightarrow \displaystyle \sf \: l =  \int \: (t - 1) {}^{2}  \sqrt{t}  \: dt \\  \\  \longrightarrow \displaystyle \sf \: l =  \int( {t}^{2}  - 2t + 1) \sqrt{t} .dt \\  \\  \longrightarrow \displaystyle \sf \: l =  \int( {t}^{  \frac{5}{2}  }  - 2t {}^{ \frac{3}{2} }  +  \sqrt{t} ).dt

We know that,

 \displaystyle \:  \sf \:  \int {x}^{n}  =  \dfrac{ {x}^{n + 1} }{n + 1}  + c

Thus,

 \longrightarrow \:  \sf \: l =  \dfrac{2 {t}^{ \frac{7}{2} } }{7}   -  \dfrac{4 {t}^{ \frac{5}{2} } }{5}  +  \dfrac{2t {}^{ \frac{3}{2} } }{3}  + c \\  \\  \longrightarrow \:  \boxed{ \boxed{ \sf l =  \dfrac{2 \sqrt{(x + 1) {}^{7} } }{7} -  \dfrac{4 \sqrt{(x + 1) {}^{5} } }{5} +  \dfrac{2 \sqrt{(x + 1) {}^{3} } }{3}   + c }}

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