Question

Refer to the attachment .


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Answer 1

explanation

(SEE ATTACHMENT )

:)

Answer 2

Answer:

• 242.62 m/s².
• 406.26 m.

Explanation:

Given :

• Initial velocity (u) = 0 m/s
• Final velocity (v) = 444 m/s
• Time taken (t) = 1.83 s

To find :

• Acceleration (a)
• Distance (s)

Solution :

Using Kinematics:

• v = u + at

Substituting:

⇒ 444 = 0 + a(1.83)

⇒ 444 = 0 + 1.83a

⇒ 444 = 1.83a

⇒ a = 444/1.83

⇒ a = 242.62 m/s²

∴ The acceleration is 242.62 m/s².

Using Kinematics:

• v² - u² = 2as

Substituting:

⇒ 444² - 0² = 2(242.62)s

⇒ 197136 = 485.24s

⇒ s = 197136/485.24

⇒ s = 406.26 m

or,

• S = ut + 1/2at²

⇒ S = 0(1.83) + 1/2 × 242.62(t)²

⇒ S = 0 + 1/2 × 242.629 × (1.83)²

⇒ S = 121.3145 × (1.83)²

⇒ S = 406.26 m

∴ The distance covered is 406.26 m.