refer to the attachment plz ans with full explanation✌️
Answers
Step-by-step explanation:
Given: Two lines x+y=6 and 2x-y=3
To find:Draw the graph of x + y=6 which intersects the X axis at A and B respectively. On the same graph paper, draw the graph of 2x-y=3 which intersects the X-axis and Y-axis at C and D respectively. E is the point of intersection of both the graphs. Find the areas of (a) ∆ECA (b) ∆EBD
Solution:
Step1: To draw x+y=6.
Put y=0 and find x,
x+0=6
x=6
A(6,0)
Put x=0 and find y
0+y=6
y=6
point B(0,6)
Step 2:To draw 2x-y=3.
Put y=0 and find x,C(1.5,0)
and point D(0,-3)
Step 3: Draw these lines,mark the intersection of both lines,point E(3,3).
Graph is attached.Fig 1
Step 4:Find area of ∆ECA
See fig 2
Area of ∆ECA=1/2×BASE×HEIGHT
=1/2×AC×EF
=1/2×(4.5)×3
=6.75 unit²
Area of ∆ECA=6.75 unit²
Step 5:Find area of ∆EBD
See fig 3
Area of ∆EBD=1/2×BASE×HEIGHT
=1/2×BD×EF
=1/2×(9)×3
=13.5 unit²
Area of ∆EBD=13.5 unit²
Final answer:
A(6,0)
B(0,6)
C(1.5,0)
D(0,-3)
E(3,3)
Area of ∆ECA=6.75 unit²
Area of ∆EBD=13.5 unit²
Hope it helps you.
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Answer:
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