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32. the two zeroes are 10,1
33. Given polynomial: 32 +9x-6
Since, = √3 is a zero, so, -√3 is a factor.
Also, =
factor.
-√3 is also a zero, so, x+√3 is also a
Hence, (x - √3)(x+√3) is a factor
i.e., ²-3 is a factor
Now, by dividing the given polynomial by a²-3, we can find out the other factors.
x2
x²-3x
-
3x
3.x3
+ 2
x² + 9x
- -
6
+1 3x2
3x³ + 2x² + 9x - 6 +
1+ 3x3 + 9x
2x2
-
6
2x² +1
0
Now, factorize ² - 3x + 2.
= (x - 1)(x-2).
= x(x - 2) — 1(x-2)
⇒ x = 1,2 are the other zeroes.
Hence, all the zeroes of polynomial¹-32³-²
+9.x - 6 are 1.2. √3,-√3.
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