Refer to the given data regarding results of F2 generation of Mendelian cross. Plants with round and yellow coloured seeds:-315. Plants with round and green coloured seeds :-108 .Plants with wrinkled and yellow coloured seeds:- 101.Plants with wrinkled and green coloured seeds:-32. What would be the phenotype of Fı generation regarding given data of F2 generation? What would be the genotype of parental generation regarding the given result of F2 generation? if a plant with wrinkled and green coloured seeds is crossed with the plant having wrinkled and yellow coloured seeds, what will be the probable phenotype of offsprings? OR What will result when plant YyRr is self-pollinated?
Answers
Answer:
i) Pisum sativum is the scientific name of a pea plant.
ii) The genotype of the F1 generation is RrYy.
iii) The phenotypic ratio of F2 generation is 9:3:3:1 where phenotypes of off springs are - Round and Yellow, Round and green, Wrinkled and yellow and Wrinkled and green.
iv) According to Mendel's law of independent assortment, during the inheritance of two or more characters, the assortment of individual traits takes place independently during gamete formation. Thus each allele of a pair segregates independently and each gamete formed contains one allele of that trait.
v) F1genotype is RrYy. So, the possible gamete combinations are
1. RY= Round yellow
2. rY = Wrinkled yellow
3. Ry= Round green
4. ry = Wrinkled green
Answer:
- The phenotype of F1 generation will be round and yellow (RrYy) regarding the given data of F2 generation.
- The genotype of parental generation in F2 will be RrYy.
- When a wrinkled and green coloured seed is crossed with wrinkled and yellow coloured seed then the phenotype of offsprings will be wrinkled and yellow seed and wrinkled and green seed.
- When the plant YyRr is self pollinated then the phenotype is round and yellow, round and green, wrinkled and yellow, wrinkled and green.
Here, RR is round
Rr is round
rr is wrinkled
YY is Yellow
Yy is Yellow
yy is green