Question

Refer to Top View

Find the mid-point of the segment joining the points J (6, 17) and I (9, 16).

(i) (33/2,15/2)

(ii) (3/2,1/2)

(iii)(15/2,33/2)

(iv) (1/2,3/2)​

Answer 1

Answer:

(iii) (15/2,33/2)

Step-by-step explanation:

Formula to find mid point -   $\frac{(x1 +x2)\\}{2}$ ,  $\frac{(y1+y2)}{2\\}$

x = $\frac{(x1 +x2)\\}{2}$

  = $\frac{6+9}{2}$

  = $\frac{15}{2}$

y =  $\frac{(y1+y2)}{2}$

  = $\frac{17+16}{2}$

  = $\frac{33}{2}$

∴ (iii) (15/2,33/2)

Hope it helps :)

Answer 2

SOLUTION

TO CHOOSE THE CORRECT OPTION

The mid-point of the segment joining the points J (6, 17) and I (9, 16).

(i) (33/2,15/2)

(ii) (3/2,1/2)

(iii)(15/2,33/2)

(iv) (1/2,3/2)

CONCEPT TO BE IMPLEMENTED

For the given two points $\sf{A( x_1 , y_1) \: \: and \: \: B( x_2 , y_2)}$

The midpoint of the line AB is

$\displaystyle \sf{ \bigg( \frac{x_1 + x_2}{2} , \frac{y_1 + y_2}{2} \bigg)}$

EVALUATION

Here the given points are J (6, 17) and I (9, 16).

Hence the required mid-point of the segment joining the points J (6, 17) and I (9, 16) is

$\displaystyle \sf{ = \bigg( \frac{6 + 9}{2} , \frac{17 + 16}{2} \bigg)}$

$\displaystyle \sf{ = \bigg( \frac{15}{2} , \frac{33}{2} \bigg)}$

FINAL ANSWER

Hence the correct option is

$\displaystyle \sf{ (iii) \: \: \: \bigg( \frac{15}{2} , \frac{33}{2} \bigg)}$

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