Reffer to the attechment
Answers
Answer:
Ans. 5) The breadth of a rectangular plot of land if its area is 440 m2 and the length is 22 m is 20 m.)
Ans.6) A circle of radius 2 cm is cut out from a square piece of an aluminum sheet of side 6 cm. What is the area of the left over aluminum sheet? (Take π = 3.14) Therefore, the area of the aluminum sheet left is 23.44 cm2.
Ans.7) Here, PQ=10m and PS=300m, EH=10m and EF=700m
And KL=10m and KN=10m
Area of roads = Area of PQRS+Area of EFGH−Area of KLMN
[∵ KLMN is taken twice, which is to be subtracted]
=PS×PQ+EF×EH−KL×KN
=(300×10)+(700×10)−(10×10)
=3000+7000−100
=9,900m
2
Area of road in hectares, 1m
2
=
10000
1
hectares
∴9,900m
2
=
10000
9900
=0.99 hectares
Now, Area of park excluding cross roads = Area of park−Area of road
=(AB×AD)−9,900
=(700×300)−9,900
=2,10,000−9,900
=2,00,100 m
2
=
10000
200100
hectares=20.01 hectares.
Step-by-step explanation:
teeno ke answer hai 5,6,7.