Question

Refracaire Index of benzena is 1.50, speed of
light in vaccum is 3x10^8 m/s then Speed of
light in benzene​

Answer 1

Given :

Refractive index of benzene = 1.5

Speed of light in vacuum = 3×10⁸ m/s

To Find :

Speed of light in benzene.

Solution :

$\star$ Refractive index of a medium is defined as the factor by which speed of light reduces as compared to the speed of light in vacuum.

$\dag\:\underline{\boxed{\bf{\purple{\mu=\dfrac{c}{v}=\dfrac{speed\:of\:light\:in\:vacuum}{speed\:of\:light\:in\:medium}}}}}$

• More (less) refractive index implies less (more) speed of light in that medium, which therefore is called denser (rarer) medium.
• It is an unitless as well as dimensionless physical quantity.

By substituting the given values;

$\sf:\implies\:1.5=\dfrac{3\times 10^8}{v}$

$\sf:\implies\:v=\dfrac{3\times10^8}{1.5}$

$:\implies\:\underline{\boxed{\bf{\orange{v=2\times10^8\:ms^{-1}}}}}$

Answer 2

Given :

Refractive index of benzene = 1.5

Speed of light in vacuum = 3×10⁸ m/s

To Find :

Speed of light in benzene.

Solution :

$\star$ Refractive index of a medium is defined as the factor by which speed of light reduces as compared to the speed of light in vacuum.

$\dag\:\underline{\boxed{\bf{\purple{\mu=\dfrac{c}{v}=\dfrac{speed\:of\:light\:in\:vacuum}{speed\:of\:light\:in\:medium}}}}}$

More (less) refractive index implies less (more) speed of light in that medium, which therefore is called denser (rarer) medium.

It is an unitless as well as dimensionless physical quantity.

By substituting the given values;

$\sf:\implies\:1.5=\dfrac{3\times 10^8}{v}$

$\sf:\implies\:v=\dfrac{3\times10^8}{1.5}$

$:\implies\:\underline{\boxed{\bf{\orange{v=2\times10^8\:ms^{-1}}}}}$