Question

Refractive Index of a medium is under root 2. find its Critical Angle​

Answer 1

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Answer 2

The critical angle is 45 degrees.

Explanation:

Given that,

The refractive index of medium, $n=\sqrt{2}$

We need to find the critical angle. The relation between the refractive index and the critical angle is given by :

$n=\dfrac{1}{sin\theta_c}$

$\theta_c$ is the critical angle

$sin\theta_c=\dfrac{1}{n}$

$sin\theta_c=\dfrac{1}{\sqrt{2}}$

$sin\theta_c=0.7071$

$\theta_c=44.99^{\circ}$

or

$\theta_c=45^{\circ}$

So, the critical angle is 45 degrees. Hence, this is the required solution.

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