Question

Refractive index of index of four substances A B C and D are 1.31,1.43,1.33,2.4 respectively the speed of light is maximum in

Answer 1

EXPLANATION:

In lesser densely substance, Light has more speed than greater densely substance.

COMPARISON:

Given :

A(1.31)

B(1.43)

C(1.33)

D(2.4)

In the above densities, A is the least density substance.

FINAL ANSWER :

A(1.3) has maximum speed of light and D(2.4) has least speed of light.

Answer 2

VELOCITY IS MAX IN MEDIUM A.

Let's see why :

• The refractive index of any media is defined as the ratio of velocity of light in vacuum to the velocity of light in the medium.

$\boxed{\mu = \dfrac{velocity \: in \: vacuum}{velocity \: in \: medium} }$

• Now, since the velocity of light in vacuum is constant and equal to 3 × 10⁸ m/s, we can say:

$\boxed{\implies \mu \propto \dfrac{1}{velocity \: in \: medium}}$

• So, lower value of refractive index will correspond to higher the velocity of light in that medium.

The minimum refractive index in the given options is 1.31 (medium A)

So, medium A will have max velocity of light.