Physics, asked by awarisriharsha, 1 year ago

refractive index of prism

Answers

Answered by Anonymous
2


refractive index of prism(n)=sin{(A+2)/2}/sin{A/2}

 where A  is angle of the taken prism.

             D is angle of minimum deviation of the prism.

Answered by magzzzz
1
Sin{(A+D)/2)} = n.Sin(A/2) Therefore, n = Sin(A+D/2)/Sin(A/2). WHERE, deviation = D
Similar questions