refractive index of the equi convex lens is 1.5 and it's radius of curvature is 45 cm then find its focal length
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Let, the radius of curvature of each face of the lens be x cm. Then R1 = + x cm and R2= – x cm. Also, Refractive index f glass,
m.............
Let, the radius of curvature of each face of the lens be x cm. Then R1 = + x cm and R2= – x cm. Also, Refractive index f glass,
m.............
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