refractive index of water and benzene with respect to air are 1.33 and 1.50 respectively calculate the refractive index of benzene with respect to water
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the refractive index of benzene with respect to water is 0.89
the refractive index of water with respect to air is 1.33
n = v1 / v2
1.33 = 3 . 10 raise to 8 m /s / v2
v2 = 3 . 10 raise to 8 m /s / 1.33
v2 = 2.25 . 10 raise to 8
n = v1 /v2
1.50 = 3 . 10 raise to 8 m /s / v2
v2 = 3 . 10 raise to 8 m /s / 1.50
v2 = 2 . 10 rasie to 8 m/s
n = v2 / v1
n = 2 . 10 rasie to 8 m/s / 2.25 . 10 raise to 8
n = 0.89
( here v1 is the velocity of light in water , v2 is the velocity of light in benzene )
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