Question

Refractive indices of media P, Q, R and S are
P-1.31 Q-1.33 R-1.52 S-1.50
In which of the four media the speed of light is maximum and minimum?

Answer 1

Answer:

maximum speed is P"

minimum speed is R

Answer 2

Given,

Refractive index,

P = 1.31, Q = 133, R = 1.52, S = 1.50

To Find,

Maximum and Minimum speed in four media.

Solution,

We can solve this mathematical problem using mathematical formulas.

μ = refractive index of medium.

C = speed of light.

Speed of light, V = $\frac{C}{u}$

As we know,  μ = $\frac{C}{V}$

Since C = constant [speed of light].

So, μ ∝ $\frac{1}{V}$ .  Then V ∝ $\frac{1}{u}$

⇒ V = $\frac{K}{u}$    [ K = constant = 1]

Hence, for maximum speed, μ should be minimum.

And, for minimum speed, μ should be maximum.

1. $V_{min} = \frac{1}{u_{max} }$ , So 'V'  is min in 'R'.
2. $V_{max} = \frac{1}{u_{min} }$ , So 'V' is maxed in 'P'.

Therefore,

Speed of light will be maximum in P having minimum μ.

Speed of light will be minimum in R having maximum μ.