Question

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Q. ᴛʜᴇ ᴀʀᴇᴀ 'ᴀ' ᴏғ ᴀ ʙʟᴏᴛ ᴏғ ɪɴᴋ ɪs ɢʀᴏᴡɪɴɢ sᴜᴄʜ ᴛʜᴀᴛ
ᴀғᴛᴇʀ ᴛ sᴇᴄᴏɴᴅ ᴀ=3ᴛ²+ᴛ/5+7. ᴄᴀʟᴄᴜʟᴀᴛᴇ ᴛʜᴇ ʀᴀᴛᴇ
ᴏғ ɪɴᴄʀᴇᴀsᴇ ᴏғ ᴀʀᴇᴀ ᴀғᴛᴇʀ 5 sᴇᴄᴏɴᴅs.​

Answer 1

Answer:

Hi mate here is ur answer

Given

$</u></em><em><u>A</u></em><em><u>= {3t}^{2} + </u></em><em><u>t</u></em><em><u>/</u></em><em><u>5</u></em><em><u>+</u></em><em><u>7$

To find

Rate of increase of area after 5 sec

So,

For rate we have to differentiate 'A'

:- A=6t+1/5( 7 is constant)

Now for finding rate we have to put the value of 't' in A

We get,...

A=6×5+1/5=30+0.2=30.2

SO RATE OFINCREASE OF AREA AFTER 5 SEC =30 .2 UNIT

HOPE IT HELPS

THANKU

Answer 2

Answer attached

Hope it helped u☺️✌️

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