Question

Regression equation of two veriables as follows:
10x-10y=64
40x-18y=320

Answer 1

Answer:

here

10x – 10y = 64

10x = 64 + 10y

$x = \frac{64 + 10y}{10}$

now we put the above value of x in equation. 40x –18y=320

$40( \frac{64 + 10y}{10}) - 18y = 320$

$256 + 40y - 18y = 320 \\ 22y = 320 - 256 \\ 22y = 64 \\ y = \frac{64}{22} \\ \\ y = \frac{32}{11}$

now put value of y in equation

10x–10y= 64

$10x - 10( \frac{32}{11} ) = 64 \\ \\ \frac{110x - 320}{11} = 64 \\ \\ 110x - 320 = 704 \\ 110x = 704 + 320 \\ 110x = 1024$

$x = \frac{1024}{110} \\ \\ x = \frac{512}{55}$