Question

regroup and factorise ay+20+4y-5a​

Answer 1

Answer:

We xan re-arrange and write it as:

ay+5a+4y+20

(ay+5a)+(4y+20)

From the above equation we can take a and 4 as common.

a (y+5)+4 (y+5)

(y+5)(a+4)

Step-by-step explanation:

HOPE THIS WILL HELP YOU:)

Answer 2

4y +ay-5a+20

y(4+a)-5(4+a)

(y-5)(4+a)