Regula
Given that a body falling freely passes through
5390 cm in the sixth second. Find the value of g
(1) 1000 cm/s2 (2) 900 cm/s
(3) 950 cm/s (4 980 сmisa
Answers
Answered by
8
Answer:
3)950 cms is the answer
Answered by
8
Hello Dear,
◆ Answer -
g = 980 cm/s^2
◆ Explaination -
Distance travelled by freely falling body in 5 s is -
s1 = 1/2 gt1^2
s1 = 1/2 × g × 5^2
s1 = 25g/2
Distance travelled by freely falling body in 6 s is -
s2 = 1/2 gt2^2
s2 = 1/2 × g × 6^2
s2 = 18g
Distance travelled by body in 6th s is -
s = s2 - s1
5390 = 18g - 25g/2
5390 = g × (18-25/2)
g = 5390 × 2 / 11N
g = 980 cm/s^2
Therefore, value of g is 980 cm/s^2.
Thanks dear.
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