Question

rehman has 50 coins in his purse which are of 20 paisa and 25 paisa denomination. The value of all coins is Rs. 11.25 find the number of couns of each denomination

Answer 1

Answer:-

Given:

Total number of coins = 50

Let the number of 20 P coins be x and number of 25 P coins be y

→ x + y = 50 -- equation (1)

And,

The value of all the coins = Rs. 11.25

Value of 20 P coins = 20* x = 20x P

Value of 25 P coins = 25 * y = 25y P

Hence,

20x + 25y = 11.25 * 100 P

→ 5 (4x + 5y) = 1125 P

→ 4x + 5y = 1125 / 5

→ 4x + 5y = 225 -- equation (2)

Multiply equation (1) by 4 and subtract equation (1) from (2).

→ 4x + 5y - 4 ( x + y) = 225 - 4(50)

→ 4x + 5y - 4x - 4y = 225 - 200

→ y = 25

→ Number of 20 P coins = 25

Substitute the value of y in equation (1)

→ x + y = 50

→ x + 25 = 50

→ x = 50 - 25

→ x = 25

→ Number of 25 P coins = 25

Hence, there 25 - 25 P coins and 25 - 20 P coins along with Rehman.