Question

Rehmat Chacha takes a loan of amount of 240000 from a bank for constructing a building at the rate of simple interest of 12% per annum after 1 year of taking the loan he rents the house at the rate of rupees 5200 per month. let me determine the number of years he would take to repay his loan along with interest from the income of house rent.​

Answer 1

The number of year is 9 years.

Given

Principal ( P ) = Rs. 2,40,000

Rate ( r ) = 12%

Number of years ( n ) = ?

Simple Interest ( S . I ) = $\frac{ (P * r * t )}{100}$

Before 1 year, the simple interest is :

                           S . I = $\frac{ (P * r * t )}{100}$

                                  = $\frac{2,40,000 * 12 *n}{100}$

                           Amount = Principal + Simple Interest

                           Amount = 2,40,000 + $(\frac{2,40,000*12*n}{100} )$   -----> ( 1 )

After 1 year, the amount is :

                            Amount = 5,200 × 12 × ( n - 1 )   -----> ( 2 )

Now, equate equation ( 1 ) and equation ( 2 ),

 2,40,000 + $(\frac{2,40,000*12*n}{100} )$ = 5,200 × 12 × ( n - 1 )

 2,40,000 + ( 2400 × 12 × n ) = 5,200 × 12 × ( n - 1 )

Divide the above equation by 100, it gives

 2400 + 24 × 12 × n = 52 × 12 × ( n - 1 )

Divide the above equation by 12, it gives

 200 + 24 × n = 52 × ( n - 1 )

 200 + 24 × n = 52n - 52

 200 + 52 = 52n - 24n

          252 = 28 n

               n = 252 / 28

                  = 9

Therefore, the number of years is 9 years.

To learn more...

Rehmat Chacha takes a loan of amount of 240000 from a bank for constructing a building at the rate of simple interest of 12% per annum after 1 year of taking the loan he rents the house at the rate of rupees 5200 per month. let me determine the number of years he would take to repay his loan along with interest from the income of house rent.​

brainly.in/question/14037895

       

 

                           

Answer 2

Step-by-step explanation:

Principal ( P ) = Rs. 2,40,000

Rate ( r ) = 12%

Number of years ( n ) = ?

Simple Interest ( S . I ) = \frac{ (P * r * t )}{100}

100

(P∗r∗t)

Before 1 year, the simple interest is :

S . I = \frac{ (P * r * t )}{100}

100

(P∗r∗t)

= \frac{2,40,000 * 12 *n}{100}

100

2,40,000∗12∗n

Amount = Principal + Simple Interest

Amount = 2,40,000 + (\frac{2,40,000*12*n}{100} )(

100

2,40,000∗12∗n

) -----> ( 1 )

After 1 year, the amount is :

Amount = 5,200 × 12 × ( n - 1 ) -----> ( 2 )

Now, equate equation ( 1 ) and equation ( 2 ),

2,40,000 + (\frac{2,40,000*12*n}{100} )(

100

2,40,000∗12∗n

) = 5,200 × 12 × ( n - 1 )

2,40,000 + ( 2400 × 12 × n ) = 5,200 × 12 × ( n - 1 )

Divide the above equation by 100, it gives

2400 + 24 × 12 × n = 52 × 12 × ( n - 1 )

Divide the above equation by 12, it gives

200 + 24 × n = 52 × ( n - 1 )

200 + 24 × n = 52n - 52

200 + 52 = 52n - 24n

252 = 28 n

n = 252 / 28

= 9

Therefore, the number of years is 9 years. And plz mark me as brainlest