Math, asked by malaysialee2, 7 months ago

Reina and Sam are multiplying (84)5 (73)9. Reina's Work Sam's Work (84)5 (73)9 = 84 + 573 + 9 = 89712 (84)5 (73)9 = 84⋅573⋅9 = 820727 Is either of them correct? Explain your reasoning. (5 points)

Answers

Answered by arshikhan8123
1

Concept

When we multiply a value by the sum of two or more integers, we exploit the distributive property of multiplication over addition. For example, consider the expression: 5(5 + 9). You may solve this formula by multiplying 5 by both addends. As a result, 5(5) + 5(9) = 25 + 45 = 70.

The distributive property of multiplication over addition is applied when you multiply a value by a sum.

Given

to multiply - (84)5 × (73)9.

Find

(84)5 × (73)9., who has done this multiplication correctly.

Solution

Reena's work =(84)5 × (73)9  = 84 + 573 + 9 = 89712

which is wrong, due to incorrect use of the distributive property.

Sam's Work = (84)5 ×  (73)9 = 84 × 573 × 9 = 820727

which is correct

Actually,  they are doing or multiplying using exponents.

#SPJ3

Answered by tanvigupta426
1

Answer:

They are multiplying using exponents.

Step-by-step explanation:

Given:

Reina and Sam are multiplying (84)5 (73)9.

Reina's Work Sam's Work

(84)5 (73)9 = 84 + 573 + 9 = 89712 (84)5 (73)9 = 84*573*9 = 820727

When we multiply a value by the sum of two or more integers, we use the distributive property of multiplication over addition.

Step 1

For illustration, evaluate the phrase:

$5(5+9)$.

You may solve this formula by multiplying 5 addends. As a result,

$5(5)+5(9)

=25+45

=70$.

The distributive property of multiplication over addition exists used when you multiply a value by a sum.

Step 2

To multiply - (84)5 $\times(73) 9$.

Find $(84) 5 \times(73) 9$, who has done this multiplication correctly.

Reena's work $=(84) 5 \times(73) 9

=84+573+9

=89712$

which is wrong, due to incorrect use of the distributive property.

Step 3

Sam's Work $=(84) 5 \times(73) 9

=84 \times 573 \times 9

=820727$

which is correct

Actually,  they are multiplying using exponents.

#SPJ3

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