Rekha borrowed rupees 40000 for 3 years at 10% per annum compound interest calculate the interest paid by her for the second year
Lipimishra2:
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8 class
I m in 7th
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Answers
Answered by
2
SI = PRT/100, SI = 40000×2×10/100 = 8000
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Answered by
29
P1=40000 rupees.
T=3 years.
R=10%
T1=1 year.
Interest(I1)=(PRT)/100
=(40000*10*1)/100
=4000 rupees.
P2=P1+I1
=40000+4000
=44000 rupees.
T2=1 year
Interest(I2)=(P2*R*T2)/100
=(44000*10*1)/100
=4400 rupees.
Answer: the interest for the second year is 4400 rupees.
T=3 years.
R=10%
T1=1 year.
Interest(I1)=(PRT)/100
=(40000*10*1)/100
=4000 rupees.
P2=P1+I1
=40000+4000
=44000 rupees.
T2=1 year
Interest(I2)=(P2*R*T2)/100
=(44000*10*1)/100
=4400 rupees.
Answer: the interest for the second year is 4400 rupees.
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