Question

rekha can open a 2 m wide door by minimum force of 2.5n . find the moment of force needed to open the door
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Answer 1

Given,

Force = 2.5 N

Distance = 2 m

Moment of force = (Force×Distance)

1. = (2.5×2)Nm
2. = 5 Nm

Answer 2

moment of force = force * perpendicular distance

                            = 2.5* 2

                            = 5 Nm