Math, asked by visheshrathorepbpa2c, 1 year ago

Rekha is 3 year older than anita.five year ago Rekha's age was foyr times Anita's age.find the ages of Rekha and Anita.


ridhima12: according to the question the the age of Rekha is equals to 3x and Anita age will be x 5 years ago their ages will be Rekha age age is equals to 3x - 5 and anita's age is equals to x minus 5 then 45 is equals to 3 x minus 5

Answers

Answered by Panzer786
95
Hey !!

Let Anita's present age is X years.

Present age of rekha = ( X + 3 ) years.

five years ago age of Anita = ( X - 5).

And,

Five years ago age of rekha = ( X + 3 - 5) years. = ( X - 2 ) years.

According to question,

X - 2= 4 ( X - 5)

X - 2= 4X - 20

4X -X = -2 +20

3x = 18 years

X = 6 years.
Present age of Anita = X = 6 years.

And,

Present age of rekha = X + 3 =6+3 = 9 years.

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Answered by Ankit02
88
Your Answer
✍✍✍✍✍

Let the present age of Anita be x years.
then,
Age of Rekha = x+3 years.

Five years ago,
Age of Anita = x-5 years .
Age of Rekha = x+3-5
= x-2 .

According to Question :-
x-2 = 4(x-5)
x-2 = 4x -20
x-4x = -20+2
-3x = -18
x = 6 years .


Anita = 6years.

Rekha = 9years .


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