Question

Rekha is three years older than Anita. five years ago Rekha's age was four times Anita's age. Find the ages of Rekha And Anita.

Let Anita's present age =x years
present age of Anita=(x+3)years
Five years ago of
Rekha(x+3-5)years =(x-2)
According to question
(x-2)=4 (x-5)
(x-2)=4x-20
4x-x=-2+20
3x=18
x=18÷3
Anita's present age =6 years
present age of Rekha=6+3=9years
Bishwajeet kumar singh Rajput​

Answer 1

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Step-by-step explanation:

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Answer 2

Age of Anita is 6 years and age of Rekha is 9 years

GIVEN

Rekha is three years older than Anita. five years ago Rekha's age was four times Anita's age.

TO FIND

Find the ages of Rekha And Anita.

SOLUTION

We can simply solve the above problem as follows;

Let the present age of Anita = x

Present age of Rekha = x + 3

It is given that five years ago Rekha's age was four times Anita's age.

The algebraic thus formed;

(x+3-5 )=4 (x-5)

x -2 = 4x -20

Rearranging the like terms;

-2 +20 = 4x - x

18 = 3x

x = 18/3 = 6

Hence,

Hence, Age of Anita = x = 6 years

Hence, Age of Anita = x = 6 years Age of Rekha = x + 3 = 6+3 = 9 years

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