Rekha is walking on the road with a uniform velocity of 9 m/s as shown. As she crosses Point A, five constant forces act on her as shown. She then takes another 6 seconds to travel from Point A to Point B which is 54 meters away. Find the magnitude of the force F
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Technically the magnitude of the force should be Zero.
As, Here, u=9m/s
S=54m
T=6s
We know, F=ma
Let the acceleration of the body be a m/s^2.
Then, Using the formula:
S= ut+1/2at^2
54 = 6*9 + a/2 * 6*6
54-54 = 18a
18a = 0
So, a = 0
Now, F=ma
Putting a,
F=m*0
So, F = 0 (ans)
As, Here, u=9m/s
S=54m
T=6s
We know, F=ma
Let the acceleration of the body be a m/s^2.
Then, Using the formula:
S= ut+1/2at^2
54 = 6*9 + a/2 * 6*6
54-54 = 18a
18a = 0
So, a = 0
Now, F=ma
Putting a,
F=m*0
So, F = 0 (ans)
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