Question

related to Circle lesson

Answer 1

$\Huge{\boxed{\pink{\mathbb{ANSWER}}}}$

To show,

△PAB ≅△OAB

In △PAB and△OAB,

AB = BA (common)

∠QBA = ∠BAP (alternate interior angles)

∠QAB = ∠ABP (alternate interior angles)

Therefore, △PAB ≅△OAB.

$\large{\bold{\underline{Hence,\:showed.}}}$