Question

relation between average molar kinetic energy of n2 and h2 at same temperature is​

Answer 1

KE1=KE2.



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Answer 2

The average molar Kinetic Energy of N₂ and H₂ at the same Temperature are same.

Kinetic energy of a certain amount of gas of mass m is = $\frac{1}{2}$ m v² [Here, v = r.m.s velocity of the gas]

We know, the r.m.s velocity = $\sqrt{\frac{3RT}M} }$

Here, T = Temperature

         R = Universal gas constant

         M = Molecular weight of the gas

∴ K.E. =  $\frac{1}{2}$ × m × $\frac{3RT}{M}$ [By putting the value of v]

⇒ K.E. = $\frac{3}{2}$ n RT [n = number of moles of the gas, n= m/M]

For 1 mole of gas,

K.E. =  $\frac{3}{2}$ RT

So,

• The average molar K.E. does not depend on the molecular weight of the gas.
• It depends only upon the Temperature.

As the temperature is same, so, the average molar kinetic energy of N₂ and H₂ will also be same.