Relation between distance covered and time of
moving particle is s = 2t³ - 4t² + 3t. What will be the
velocity and acceleration after 3sec?
Answers
Answered by
11
Answer :
Relation between distance covered and time of moving particle is provided
- s = 2t³ - 4t² + 3t
We have to find velocity and acceleration of particle after 3s.
_________________________________
◈ Instantaneous velocity :
➳ v = (Δt ➝ 0) Δs/Δt = ds/dt
➳ v = d(2t³ - 4t² + 3t)/dt
➳ v = 6t² - 8t + 3
➳ v = 6(3)² - 8(3) + 3
➳ v = 6(9) - 24 + 3
➳ v = 54 - 21
➳ v = 33 m/s
◈ Instantaneous acceleration :
⇒ a = (Δv ➝ 0) Δv/Δt = dv/dt
⇒ a = d(6t² - 8t + 3)/dt
⇒ a = 12t - 8
⇒ a = 12(3) - 8
⇒ a = 36 - 8
⇒ a = 28 m/s²
Similar questions