Question

Relation between distance covered s and time t of a moving particle is, s = 2t3-4t2+3t. What will be the velocity and acceleration after 3 second?

Answer 1

Answer:

Velocity = 33 m/s

Acceleration = 28 m/s^2

Step-by-step explanation:

S = 2t^3 - 4t^2 + 3t

Now, we know, V= ds/dt

Therefore, V = d(2t^3 - 4t^2 + 3t)/dt

V = 6t^2 - 8t +3

Therefore after t=3 sec

V = 6(3)^2 - 8(3) +3

V = 54 - 24 + 3 = 33

Velocity = 33 m/s

Now, we again know, a = dV/dt

a= d (6t^2 - 8t +3) /dt

a= 12t -8

Therefore after t=3 sec

a= 12(3) -8

a= 36-8 =28

Acceleration = 28 m/s^2

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