relation between electric potential difference and drift velocity of free electrons in the conductor.
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½mv²=qV( V=potential difference, v=drift velocity, m=mass of charged particle, q=charge on particle)
(V/R)=nEAVd ( V- Potential, n- No: of electrons, A- Area of cross section of the conductor, Vd- Drift velocity.. R- Resistance of the conductor.)
(V/R)=nEAVd ( V- Potential, n- No: of electrons, A- Area of cross section of the conductor, Vd- Drift velocity.. R- Resistance of the conductor.)
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Answer:
Explanation:
We know that
if dE = electric field
dV = pot. difference
dr= distance considered
dE= -dV/dr
From this E = V/ l
l= length of the conductor
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