Question

Relation between equivalent conductance and molar conductance for h2so4

Answer 1

Its conductance is equal to equivalent conductance, Λ. containing this electrolyte is called specific conductance, κ. solution containing one mole of an electrolyte is known as molar conductivity.

This depends on the difference between molar mass and equivalent weight. Molar mass used to be called molecular weight and in the case of H2SO4 is 98.08. (I will not go into units and slight variations in definition over time).

If we fully neutralize H2SO4 with NaOH it takes two moles of NaOH to neutralize one mole of H2SO4. Thus the equivalent weight is half the molar mass, and for H2SO4 is 49.04.

Thus for H2SO4 the molar conductance will be twice the equivalent conductance.

Equivalent weights are a rather old-fashioned term (and thus familiar to old chemists like me). They were particularly used in titration, where one equivalent weight per liter was defined as normal, represented by N. These days I think it is best to stick to moles and molar quantities, but you may at some point have to use data from old literature.

Answer 2

Answer: $\lambda_{m}=2\times \lambda_{eq}$

Explanation:

Equivalent conductivity is defined as the conductance of all the ions produced from one gram equivalent of the electrolyte dissolved in $Vcm^3$ of the solution when the distance between the electrodes is one cm and the area of electrodes is so large that whole of the solution is contained between them. It is represented by $\lambda_{eq}$

Molar conductivity is defined as the conductance of all the ions produced from one mole of the electrolyte dissolved in $Vcm^3$ of the solution when the distance between the electrodes is one cm and the area of electrodes is so large that whole of the solution is contained between them. It is represented by $\lambda_{m}$

Relation between equivalent conductance and molar conductance:

$\lambda_{m}=n\times \lambda_{eq}$

where n= basicity of acids

As For $H_2SO_4$ , n =2

$H_2SO_4\rightarrow 2H^++SO_4^{2-}$

As $H_2SO_4$ dissociates to give 2 $H^+$ and thus it has basicity of 2.

$\lambda_{m}=2\times \lambda_{eq}$