Question

Relation between height of radio tower and transmission distance

Answer 1

hey mate your answer






The transmitted field intensity decreases as the inverse square of the distance. This means that doubling the height of an antenna from 35 to 70 feet will reduce the potential for interference by 75%.
Until August 8, 1991, the Warsaw radio mast was the world's tallest supported structure on land; its collapse left the KVLY/KTHI-TV mast as the tallest. There are over 50 radio structures in the United States that are 600 m (1968.5 ft) or taller.

Answer 2

Answer:

PQ=h

T

(heightofantenna)

PS=PT=d

From right angled ΔOTQ, we get

OQ

2

=OT

2

+QT

2

Here OQ=R+h

T

QT=PT=d

OT=R=Radiusofearth

(R+h t )

2 =R 2 +d 2R 2 +h t2 +2Rh T =R 2 +d 2 d 2 =h T2 +2Rh T d 2 =2Rh T

[1+ 2Rh T ]2Rh T

<<1d 2 =2h T Rd= 2h T R

the maximum distance d

M , between Transmitting & receiving antennas is given by

d=d T +d R

d= 2Rh T + 2Rh R

d T

=horizon for transmitting antenna

d R

=horizon for receiving antenna

h T

=height of transmitter

h R

=height ofreceiver

d=maximum distance of broadcast