Relation between K.E and momentum of a same body is
Answers
Answer:
Initially, the spring is compressed between the blocks. The spring is then released and pushes the two blocks apart. In this system momentum is conserved, and as shown previously, the kinetic energy of the smaller block of mass M2 is larger than the kinetic energy of the larger and heavier block of mass M1. As a result, the velocity of the smaller block V2 is greater than the velocity of the larger block V1. Since momentum is conserved the velocities of the two blocks are related by the following equation: M1V1 = M2V2.
As a result, most of the energy of the spring goes into the smaller and lighter block. This is just the nature of the physics at work which we arrive at using mathematics. If the stiffness of the spring is k, the elastic energy of the spring when compressed is (1/2)ks2, where s is the amount that the spring is compressed.
Answer:
if the body weight is constant then it is directly proportional
Explanation: