relation between linear momentum and kinetic energy?
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Answered by
1
hi there k.e. = (P)^2÷2M
Answered by
3
linear momentum = p = mv
where m is mass and v is velocity
k.e = 1/2 m v ^2
multiplying numerator and denominator by m
= 1/2 m ^2 v^2 / m
= 1/2 p^ 2 / m. ( since, p =mv)
where m is mass and v is velocity
k.e = 1/2 m v ^2
multiplying numerator and denominator by m
= 1/2 m ^2 v^2 / m
= 1/2 p^ 2 / m. ( since, p =mv)
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