Relation between molar mass and vapour density mathematical method
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Explanation:
It may be defined as mass of a certain volume of a substance divided by mass of same volume of hydrogen. vapour density = mass of n molecules of gas / mass of n molecules of hydrogen. (and thus: molar mass = ~2 × vapour density) For example, vapour density of mixture of NO2 and N2O4 is 38.
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Explanation:
HERE IS UR ANSWER; ¬ ¬
PV = nRT
n= X/M
X mass of the gas
M molecualr weight of the gas
D = m/V
PV = (X/M) (RT)
P = (D/M)(RT
D =PM/RT
∵From the above the more higher the M the D is higher (vapour heavier).
The more small the M the density is smaller (vapour lighter)
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