relation between operator
∆E= E∆
Answers
Answered by
1
Answer:
∆E= E∆
Step-by-step explanation:
E(Δf(x)) = E[f(x+h)- f(x)]
= E f(x+h) - E f(x)
= f(x+2h) - f(x+h)
=Δf(x+h)
=ΔEf(x)
ΔE= ΔE
Similar questions