Question

Relation between perimeter and area of isosceles triangle

Answer 1

I don't know the relation

Answer 2

Answer:

{4 * √(2a + b) } / { b * √(2a -b) }

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Step-by-step explanation:

Assume equal side = a

unequal side/base = b

height = h = √{a² - (b/2)²}

Perimeter = 2a+b

Area = (1/2)*b*h = (1/2)*b*(√{a² - (b/2)²})

so Perimeter : Area ::   (2a+b) : (1/2)*b*(√{a² - (b/2)²})

sloving this we get = {4 * √(2a + b) } / { b * √(2a -b) }